in a pipe you can write that delta  p=lambda*L/D*qv*qv where lambda is the friction coefficient, L the length of the pipe, D the diameter

delta  p=lambda*L/D*ro*qv*qv/S/S/2

I forgot the density and the cut area of the pipe

Dear Princewill Eche-George,

To do this, use the Darcy-Weisbach relationship. Find the answer in the attached file.

With my regards

Prof. Bachir ACHOUR

Dear Princewill Eche-George,

depending on type of flow:

If you consider only stationary viscous pipe flow, the Hagen–Poiseuille law describes the relation between the mean pressure and flow in a rigid tube. The peak flow can be obtained from the parabolic flow relationship. 

In non-stationary flow this does not hold and Womersly flow profile will give better results. 

Hope this helps,

Stefan 

For "pressure head" I assume you mean frictional pressure loss.

The answer depends on many things: laminar or turbulent flow, Newtonian or non-Newtonian flow property (and which flow model best fits the laminar non-Newtonian property), etc. I am afraid the answer from Stefan in Pforzheim is not correct. There is , of course no such thing as stationary flow, alsothe Hagen-Poiseuille equation appliesto the laminar flow of a Newtonian fluid only. I am running a 2-day course which covers all this on 6 and 7 April 2016 in Milton Keynes, not far from Coventry. Let me know if you need more details. Regards, Nigel Heywood ([email protected])

Actually the answer I gave is correct in the condition of laminar stationary flow in tubes, to give a more detailed answer the question needs to be more specific. Again my answer was totally correct within the scope and just given as a hint. I assume that the person who asked the question is able to decide if conditions apply to the actual situation.

The behavior of Mr Heywood, to downvote another correct answer is not what is done in science at all. I appeal to be aware of these conventions.