Hello All,
I am doing a herbicide bioassay in glasshouse. I have to calculate the amount of herbicide solution required to prepare 1 PPM of solution. The active constituents of herbicide are as follows .
Chemical A - 33 g/L
Chemical B - 15 g/L
I did following calculations to prepare 2 L of solution
Amount of product to add = Desired PPM x Volume/Product concentration
= 1 PPM x 2 L /(33 g/L+15 g/L)
I added A and B together as product concentration
416 micro liter in 2 liter of water will give 1 PPM concentration. Could you please let me know whether this calculation is correct? If not could you please tell me how to do this kind of calculation. Thanks.
Indicative analytical procedures that are related to herbicides' solutions, they are presented in the following published papers:
DOI: 10.1080/15422110600822733
DOI: 10.1080/03067310500247678
DOI: 10.1504/IJETM.2006.010482
DOI: 10.1016/j.ces.2004.09.080
DOI: 10.1081/PFC-120018446
The preparation of herbicides' solutions it should also take into consideration the co-presentation of ionic compounds in the aqueous phase, thus determing the effects of a) ionic strength and b) (the adjustment to) the preferable pH value.
Grigorios Kyriakopoulos Thanks for your explanation. I got the attached article from internet to calculate the amount of herbicide to a desired PPM. Can you please comment on this article please. Thanks.
- Badges
- Science topic
- Similar topics
- Correction