The ratio of anode active material to cathode active material is an important factor in the design of different energy storage devices (LIBs, LICs,…).

 In theoretical works, this mass ratio is calculated using the masses of active material of one anode and one cathode. For a coin cell this ratio is correct because we have two electrodes. However, in a pouch cell normally the number of electrodes is not equal. In this case, sometimes the outer electrodes are one sided (the active material is only in one face). Therefore, the mass ratio is similar to that of two electrodes. But in some cases, the outer electrodes are double sided (the active material is placed in the two faces) and the current collector has holes. Therefore, the outermost active material takes part in the electrochemical reactions. In this last case, how do we calculate the mass ratio? I think we have to take into account the total mass of the active materials that are in the cell. Is it correct?

 Thank you

More Jose Miguel Campillo Robles's questions See All
Similar questions and discussions