Is it possible to hydrolyze the -CHO head and -OH tail of two monomer units, forming a linear stand of ß-glucose for isolation further processing (serial organic reactions) for carbyne formation
The open-chain form of a monosaccharide often coexists with a heterocyclic. units of N-acetylglucosamine, a nitrogen-containing form of glucose. It is storage polysaccharides; mainly a Bacterial polysaccharides . Its breakdown may be catalyzed by enzymes called chitinases. The glucose units in cellulose are linked in a linear fashion, and some bacteria have beta-glucosidase enzymes that hydrolyze the glycosidic bond found between two units,The cyclic pyranose and furanose forms forms of various monosaccharides, and the enzymes responsible for their metabolism are specific for this configuration is cellulase. The reaction is catalyzed by acid (H) or base (OH) and is readily reversible. In both maltose and cellobiose, theglucose units are 1-4 linked, meaning that the C-1 of one glucose is linked by a glycosidic bondto the C-4 oxygen of the other glucose. The only difference between them is in the configuration at the glycosidic bond. D-lactose (O-β-D-Galactopyranosyl-(1→4)-D-glucopyranose) is the principal carbohydratein milk and is of critical nutritional importance to mammals in the early stages of their lives. It isformed from D-galactose and D-glucose via β(1→4) linkage, and yields D-galactose and D-glucose on hydrolysis.
Perhaps you need to look at an enzymatic synthesis of beta 1,3 glucan by the enzyme, callose synthetase? It is a membrane-bound reaction using uridine diphospho glucose as its substrate. Much of that work was done back in the 1960s and 1970s.
I don't think it is possible to hydrolyze the -CHO group and the -OH group on simple sugar like glucose because they are in their simplest form. This is perhaps a new challenge.
Thank you for the new information, everyone. I agree, Adebayo Alao. The reaction I asked could be impossible but I was hoping someone may have known any novel enzymes that can catalyze such reaction in a thermodynamically stable condition. Cheers!
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