Hello,

The theoretical capacity of 330 mAh/g is related to the formation of a Li1TiO2 phase you will read in the literature that for anatase this phase is thermodynamically not suitable unless your anatase particles are arround 10 nm or smaller. So to be able to get higher capacity with anatase the primary particle size should be very small. Then you will also find in literature that amorphous TiO2 present very high capacity. Howver the storing mechanism completely differ from the latices insertion mechanism occurring in anatase. So by having a combination of nanosized anatase crystal and huge amount of amorphous phase you might reach high capacity. However the difference in mechanism coupled with the huge parasitic "surface effect" occurring in amorphous phase might result in low capacity retention upon cycling.

Thank you Ugo lafont!

if TiO2 nanotubes have anatase phase completely then can i use theoratical capacity of 330 mAh/g or I have to use 168 mAh/g for cycling performance at 0.1C rate???

It is a tricky question as sometime the C-Rate derived from the nominal capacity. This is a good approach for known systems. However, in your case you do not know what will be the nominal capacity. So it is better to use the theoretical capacity related to the Li1TiO2 phase. It is the correct approach when you develop new materials. So, you may want to use 330 mAh as current. When you will report your results, state that you use 330 mAh = 1C.

Another approach is not to speak in C rate at all and just mention the current you use for your galvanostatic measurement and the theoretical capacity of the investigated system !!!