I studied in electrode for Lithium Ion battery prepared via sol gel method. After calcination of the powder, by using FTIR, OH band was appear in the spectrum. Its -OH band will effect the performance of litiun ion battery?
The presence of -OH should effect performance negatively. If you truly have -OH, there is a possible reason for its presence. You may not have washed your sample well enough after the solgel step and calcination will not remove the base substance. An effective way to fully clean your sample will be to centrifuge with water and then do calcination.
The Group IA metals pick up water to form OH bonds very easily. I think that the technique that Richard suggests is a reasonable one. However, I would suspect that the humidity is high where you are doing the experiments. This means that calcining should be done under vacuum conditions and the transfer of material should be with minimal exposure, probably under argon.
The technique suggested by RC Stehle is suitable. Consult papers of Roger Frech for details. Actually -OH band affect performance -vely.
-OH termination group is typical for oxide powder materials (which becomes severe with decreasing particle sizes). In typical cathode fabrication process, people dry the doctor-bladed cathode film at > 100 degree C in vacuum overnight, not only to remove NMP but also to remove moistures (and supposedly the -OH groups if weakly bonded). The -OH termination group will be a source of side reaction during battery operation, and will generate HF which can (i) etching the cathode surface and lead to transition metal dissolutions (i.e., Mn, Ni, Co) and (ii) destabilize graphite SEI by multiple chain reactions. For this reason, manufacturers of battery materials try powder products storing in dry conditions.
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