The AX + BX2 = ABX3, and first the [BX6]4- forms to make the octahedral network of halide perovskites. I am pretty sure that, the halogens (X-) that coordinated to B, are coming from the breakage of the A-X bond, and after that A+ fills the spaces to complete the structure, I want to know if this statement is correct. and I appreciate it if you have any references about the A-X bond breakage. Thank you very much.
I think you are right and the reason is that in many cases the A organic cation occupies the A position of the Perovskite comes from AX only. For example, in the case of formamodinium Lead Iodide the lead Iodide PbI_2 and Formamodinium Iodide FAI (FA = CH(NH_2) are reacted in such a way that the I atom attached to the FA is breaking and attached to the PbI2 and forming the PbI_6 octahedra and FA cation occupies the center of the unit cell. In another example the dimethyl formamide (CH_3)_2NCOH, adding an OH from the water medium breaking the (CH_3)_2NCOH forms (CH_3)NH_2 and HCOO molecules. Where the (CH_3)_2NH_2 (dimethyl ammonium) occupies the A site of the Perovskite and HCOO linking one metal atom to another one and forming the Perovskite structure. So you can comfortably make this statement.
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