2 mice are born from 2 separate mothers in-utero. 1 is healthy and the other not. Their offspring are accordingly healthy and not.
2 mice are born from 2 separate mothers in-vitro. 1 is healthy and the other not. Their offspring are accordingly both healthy.
Why?
The answer. In-vitro fertilisation does not transfer the same epigenetic information from mother to offspring as does in-utero. This means that epigenetic inheritance is occurring irrespective of fertilisation state in the egg and the sperm.
Discuss...
Interestingly the rates of para-mutation and evolution in some mammals do not follow progressive rates. Look at distinct varieties' of chimps in the wild versus co-habiting ones.
Interestingly a simpler model makes more sense then trying to oversimplify a more complex one.
If environment is not driving the transferred genetic material from either F1 to F2 then how, does the methylome and genetically collocated regions of uracil substitution lead to non-expression at birth?
Healthy is healthy, sick is sick, OK. Sure it's not pure binary but nevertheless it's success of finding mates and then after that it becomes more gray.
I.e. succumbing to carcinomas ; cell atrophy at birth ; defibrillated lymph nodes etc.
Why do we always need to find and explain the chicken and egg over and over? It's inherent. No?
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