This is the formal derivation of the relativistic mass formula from the force equation and the assumption E=mc² and P=mv with v=ds/dt. The derivation is based on elementary physics and elementary mathematics (calculus) only, without referring to higher domains of mathematics or physics. But identifying the constant c in the derived mass formula m=m₀/√(1-v²/c²) is not part of this derivation. In the context of this derivation c only is an arbitrary constant which has the physical dimension of a velocity.
We begin this derivation with momentum=force*time, P=F*t, infinitesimal dP=F*dt, or F=dP/dt. Followed by energy=force*distantance,E=F*s, infinitesimal dE=F*ds, F=dE/ds. ds is a Vector therefore dE/ds=(∂E/∂sx, ∂E/∂sy, ∂E/∂sz).
Physics must be consistent, therefore the force F in both equations must be the same. F=dP/dt=dE/ds.
We now consider that P with P=mv is proportional to the mass m and conclude that this proportionality also must apply to E. We therefor set E=mc² but with an arbitrary parameter c². We select this special form because the parameter which relates mass and energy must be a velocity squared.
Inserting E=mc² and P=mv leads to d/dt(mv)=d/ds(mc²). We now consider the chain rule of calculus.
(1) d/ds=d/dv*dv/ds, dv/ds=dv/dt*dt/ds, dt/ds=1/(ds/dt)=1/v
(2) d/dt=d/dv*dv/dt
(2) leads to (3) dP/dt=dP/dv*dv/dt
(1) leads to (4) dE/ds=dE/dv*dv/dt*(1/v)
We can cancel dv/dt in (3)=(4) an bring 1/v on the other side and get
(5) v*dP/dv=dE/dv. This equation now only depends on v.
Now we consider the left side of (5) with the product rule and get
(6) v*dP/dv=v*d/dv(mv)=v²(dm/dv)+vmdv/dv=v²dm/dv +vm and
(7) dE/dv=d/dv(mc²)=c²dm/dv
Now we consider (6)=(7):
v²dm/dv+vm=c²dm/dv which leads us to dm/dv*(c²-v²)=vm. Or
(8) dm/dv=vm/(c²-v²). By division with m we get:
(9) m‘/m=vm/(c²-v²) in mathematical notation: y'/y=x/(c²-x²)
We now can formally solve the equation y'/y=x/(c²-x²). This is a differential equation from type Bernoulli. Its solution derived by integration on both sides is:
(10) ln(y)=-ln((c²-x²)/2)+C. Exponentiation leads to
(11) y=C/√(c² - v²).
Selecting the constant C as C=m₀c then formally leads to
(12) m=m₀/√(1-v²/c²).
c still is only the constant in E=mc². Within this derivation from pure mechanics, c still is an arbitrary velocity and is not yet assigned to the speed of light.
This derivation, entirely based on fundamental physics and mathematics, is devoted to people who generally doubt the concept of relativistic mass m=m₀/√(1-v²/c²).
Are there any objections?
Are there any ideas how the assignment of c to the speed of light can be proven to people who generally refuse to acknowledge relativity theory?
Can we claim that people who refuse relativity theory also would refuse this basic derivation?