If we consider the velocity of the moving train in the direction of x, if we consider R is the Lorentz factor then we get
x=Rx'-Rvt' , t=Rt'-Rvx'/c^2 , y=Ry' , and z=Rz'
In this case we refuse the reciprocity principle. Thus it is resulted there is no space-time continuum, it is only time. space is invariant. Length contraction is exist in the passed distance for rider of the moving train comparing to measured passed distance of moving train for the observer on ground as the effect of time dilation. In the case each observer creates his own picture about the location of the moving train which is related to his time. In this case according to this transformation, there is no difference if we consider the length of the train L or we consider the train as a point like.
If a train is moving according to this transformation, how can you describe the motion according to the transformation above. According to this transformation we keep on Lorentz invariance without Lorentz symmetry.
According to Einstein delta y=delta y' and delta z=delta z' ,that is depending on objectivity, which is required Lorentz symmetry to keep on Lorentz invariance.
How can you describe the motion of the moving train in x direction according to our new transformation?