Hello dear experts,
I have four solid samples of a mineral. With my naked eye, I can see clearly that they have distinguishable colors. I already have UV-Vis spectra (reflectance and absorbance) ranging from 200 to 1000 nm for each of these samples. I need to know can I determine the color of each of these samples using this UV-Vis spectroscopy and how can I do that?
Please kindly advise me.
Thanks.
What we perceive as "the color of something" is in fact the wavelength mixture that it does not absorb. This can be illustrated by the color wheel (https://www2.chemistry.msu.edu/faculty/reusch/virttxtjml/spectrpy/uv-vis/spectrum.htm): if there is one dominant absorption, the color we will perceive is the complement of that.
This is shortly described in our last publication "An UV/Vis/NIR optical absorption spectroscopic and color investigation of transition-metal-doped gahnite (ZnAl2O4 spinel) crystals grown by the flux method Michail N. Taran, Oleksii A. Vyshnevskyi, and Charles A. Geiger"
Just send me one data file in the range from 340 to 830 nm, I will make the colorimetric calculation and send you the color label. You will compare it with the color of the sample and decide whether you spectrometer works well in this respect.
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