imaginary means, physically such states can not exist due to limitations of special theory of relativity.But there exist a real (or observable)physical state with superposition of those two states.
The statements, about what ``imaginary'' and ``real'' states are, are wrong.
Quantum mechanical superpositions of any states have been observed and quantum mechanics does provide the mathematical formalism for describing them. It would be useful to study a textbook on quantum mechanics.
That is the main reason I asked that question? Quantum Mechanics is based on some fundamental postulates. some more may be hidden. I understood by your answer that there is no such mathematical explanations till now. I know that the state itself is comes under 'observable'. I may not be an expert in quantum mathematics. But I have sufficient knowledge to ask this question.(The note on this question is 'limitations of special theory of Relativity' is very important that the present QM is not able to explain). Still I will try to improve my knowledge. Thank you for your suggestion.
No! There IS a mathematical explanation for why superpositions of states are inevitable in quantum mechanics:it's the fact that Schrödinger's equation is a linear equation.
However the statement about ``real'' and ``imaginary'' states is MEANINGLESS.
Non-relativistic quantum mechanics, by definition doesn't have anything to do with special relativity.
Relativistic quantum mechanics, also, describes superpositions of states. The reason is that Schrödinger's equation, still, holds, the Hamiltonian only changes.
Fine.Thank you. Let us suppose Universe as a whole as an object and at a particular moment(considering that there is no movements or velocities of object in that position or we can say at that moment it is a standstill position of universe) can we describe in a quantum state? or superposition of states? if you say yes. or no. if it is yes i will continue my discussion. I need some further help in QM.
Now apply 'Diosi-Penrose' concept for Objective Reduction since above object(standstill Universe) follows General Relativity and space time. As per quantum mechanics the object will be there in two space time locations separated by a 'S' these are temporarily locations and forms a superposition reality but stays for a specific time. This can be calculated by penrose indeterminacy principle. In this case as the mass distribution is more so its Gravitational self energy will be more. For small quantum particles it will be less.
Here which state is real? The reduction state is real? Then what about other states? In this case there is no imaginary. All these states are real....
But a case will arise where the states are meaningless since flow of time will not exist(but time exists). Such states are imaginary(we have to imagine them). They obey special theory of Relativity but ideal condition only. Once flow of time starts, it will obey both special and General Relativity. In this case the states are real.The following two papers explained it in a classical way. Shortly it will be explained in a quantum way.
1. pubs.sciepub.com/ijp/5/4/1/
2. article.sapub.org/10.5923.j.ijtmp.20170706.01.html
I am supporting Orch-OR up to some extent. But few more add ons will modify it.
Already it started in the paper(a determenistic approach to find threshold time
Link: Values of Siva’s Constant “K” for All Fundamental Forces—A Review on Spin, Threshold Time and Quantum Entanglement.
https://file.scirp.org/pdf/JMP_2019032115392293.pdf
My next paper will explain The drawbacks in Orch-OR and necessity of decoherence and entanglement in synchronizing relativity and Quantum mechanics.
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