I have found that the AC conductivity initially decreases on doping (1 at wt %) below the undoped value and then on further doping (3 at wt %) it increases more than the undoped one in case of Cd doped ZnO. Am I correct? Is there any possible explanation or reference?
Dear Prateekji, if you can give any paper for reference to me, it will be very helpful.
Naturally, stoichiometric ZnO is an insulator; preparation provides a non-stoichiometric ZnO containing oxygen defects. This gives the n-type to ZnO.
During the doping, for low doping levels, inserting metal ions provides chemical stability in terms of stoichiometry and therefore the removal of interstitial zinc. It is expected in this case a decrease in electrical conductivity. For high doping levels, the large rate promotes an increase in the conductivity.
It is noted that some ions type such as Cu, Ni Na, can favors the p-doping of ZnO.
The low doping levels achieve a transition to an insulating state and the high doping rate changing from n-type ZnO n-type ZnO is a result for the applications of this binary.
With doping ZnO with indium, the conductivity increases, I cross that is a n-type switching to the p-type
To verify this transition np, I suggest you make a measurement Hall
Good Luck
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