The amount of solid in sodium hydroxide is the amount of sodium hydroxide pellets dissolved in distilled water to achieve the desired concentration. For example, if you use 100g of 8M sodium hydroxide; the amount of solid would be 32g.

[To achieve 1M of sodium hydroxide: 40 g would be dissolved in approximately 1000g of distilled water. Hence, 100g of 8M sodium hydroxide would contain 32g of sodium hydroxide pellets (i.e. solids). ]

For the sodium silicate solution, the supplier would provide you with the amount of water and other compounds in the solution. For example, if the solution is composed of 60% water and you use 100 g of the solution to prepare a geopolymer; the amount of solids would be equal to 40g.

If solid sodium metasilicate is used to produce sodium silicate solution; the amount of solid would be equal to the mass of the solid metasilicate present in the amount of sodium silicate solution used.

NaOH solids of (40 x M)g dissolve in 1000g distilled water to produce M molar of NaOH solution of quantity of (1000+ (40 x M))g.

For solid content of sodium silicate solution, contact supplier.

Suppose you want to add alkali activator solution of 40% of binder content, then you need to decide the ratio of NaOH and sodium silicate solution in the mix and calculate 40% amount of the same.

Thank you for your clarification.

this article explain your question ( hasnaoui et all )

Sulaem Musaddiq Laskar gave an answer

NaOH solids of (40 x M)g dissolve in 1000g distilled water to produce M molar of NaOH solution of quantity of (1000+ (40 x M))g.

This is wrong. The total solution should measure 1 litre when 40 x M)g is dissolved. Here water quantity is unknown and is to be added by observation so that the volume of solution is 1 litre

Hello,

you are right mr. Rajamane, the total volume of solution for providing specific concentration of NaOH in molar must be 1 liter. For the alkali-activated materials using NaOH, I usually provid NaOH solution in 16 M, it means that I solve 640 gram NaOH in distilled water and fill it with water to 1 liter. The density of this solution is 1436 gram according to my experiment. It means that in 1 liter 16 M NaOH solution you have 640 NaOH solid+ 796 gram distilled water). It is proposed to fill the water by volume no weight, due to alittle change of density regarding ambient temperature. Then, If I need lower concentration of NaOH, I consider the rest of water as extra water in the mixtures. For the ratio NaOH and Na2O.nSiO2 you should consider the solid ratio of both materials.

hello Mr Syamak Tavasoli , may I please know how did you find the density of 16M NaOH? and can I know how do I find the density for 10M NaOH please.

Thank you