Suppose a reaction of either oxidation or reduction of an analyte is carried out in the presence of a redox electrolyte, then as it is known the redox couple undergoes ox-red via electron transfer, therefore, why the current increases on adding the analyte successively and how this thing prevails in antigen-antibody electrochemical sensing?
If the rate of change of potential difference (Voltage) increases in a given closed circuit. It lead to increasing current in that circuit. Because more number of charges (or ions) carriers were triggered by the potential difference. When the scan rate is increased the time will be decreased.
the change of Voltage increases in circuit reduces to increase current
Thanks Sir. Your explaination has the point I'm looking for. Will you please elaborate it a bit, that would be of great help.
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