I found Landauer Limit at Hawking Temperature recovers the gravity per Planck area from an S-child black hole of any radius. I was interested by this and showed others, and they wondered why it seems curvature is related to the amount of gravity emitted such that small black holes emit at much higher energies. I found this is not only the value of gravity, but also the value of a Hawking photon. People weren't happy with the ELandauer explanation not really showing why when radius goes up, the energy in a constrained degree of spin freedom goes down.

So, after my professor said it needed more support, I found EDoF. And I found the same numbers from EDoF as I did from Landauer Limit at Hawking Temperature, which is the smallest unit of energy required to erase, or clock, a quantum state. I see that by stripping charge off of the photon, you are left with only information energy, and when considering that emission surface is a ring, ln(pi) was a good fit, and since this is a scaling factor, I tried to find a scaling factor that would describe the perservation of symmetry and amplification of energy and found ln(pi)/ln(3) described it well, a compensation for the triangular folding of quantum information from cosmic horizon to local curvature.

Try this with a 1km radius black hole, try Landauer and EDoF and GR. And you will find

GR = 1.261 x 10^-30J

ELandauer = 1.74 x 10^-30J

EDoF = 1.73 x 10^-30J

If you multiply Elandauer or EDoF by the number of Planck areas on a given black hole, you will recover the energy from GR x ln(4), because gravity is from horizon spin resolution for a four-bit emission process from entangled matter particle measurement. Now there are three ways to recover gravity and EDoF doesn't have a matter mass term or gravity. Nature populates higher EDoF energies at lower radii first and lower energies at larger radii. Nature seems to prefer to send information in a straight line, but a circle requires acceleration, and therefore more energy. Any ideas why EDoF works so well with no gravity or mass term? and you can see, if you raise the radius by an order of magnitude, the energy content will drop by the same amount.

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