I have been working with multi-machine power systems, and I have been struggling with the transformation between the *dq0* and *DQ0* frames. I will first introduce my understanding of these frames, and then ask my question about it.

In power systems, the *dq0* transformation, also called Park's transformation, consists in converting from the static *abc* frame to a rotating *dq0* frame. This transformation slightly differs from author to author depending on the choice of the leading and lagging components.

When considering multi-machine networks, usually all the devices are converted to a same rotating frame with rotation speed equal to the synchronous speed \$\omega_s\$. For this reason, this rotating frame is called synchronously rotating frame, and it is represented by *DQ0* coordinates (capital letters).

However, for transforming from *dq0* to *DQ0* and vice-versa, the transformation matrix also differ from author to author depending on the choice of the leading and lagging components. For instance, when the *q* axis and *D* axis are considered initially aligned, the following transformation matrix is used for converting from *dq0* to *DQ0*, where \$\delta\$ is the angle between the *D* and *q* axes.

$$

\begin{equation*}

T_{dqos}T_{dqoi}^{-1} =

\begin{bmatrix}

\sin{\delta} & \cos{\delta}\\ -\cos{\delta} & \sin{\delta}

\end{bmatrix}

\end{equation*}

$$

On the other hand, when the *d* axis is considered initially aligned with the *D* axis, the following transformation matrix is used (here \$\delta^{\star}\$ is the angle between *d* and *D* axes).

$$

\begin{equation}

T_{dqos}^{\star}T_{dqoi}^{\star-1} =

\begin{bmatrix}

\cos{\delta^{\star}} & -\sin{\delta^{\star}}\\ \sin{\delta^{\star}} & \cos{\delta^{\star}}

\end{bmatrix}

\end{equation}

$$

Therefore, my question is: how should I define the leading and lagging components? In the case of a multi-machine power system, should the *dq0* frames of all machines be considered either lagging or leading the *DQ0* frame?

I really appreciate any kind of help!

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