Can N Q K R all be coupled to CNBr beads, which require free -NH2? Among them, is K the most efficient binding residual? Are there any other residual that can bind CNBr beads, except the N-term one?
Xuan, I do not believe that N, Q or R will react with CNBr beads to any great extent; certainly N and Q shouldn't react due to the carboxamide groups on the side chain and R would have a very low reactivity as well. By far and away K is the residue which will react with CNBr Sepharose or beads, as well as with the N-terminal amino group. Performing your reaction at a pH somewhere between 7.5 - 8.5 is probably a good first try, and avoid Tris buffers for the coupling reaction as they will also react with the CNBr and you will just end up with an immobilised Tris column. Hope this helps. Dave
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