The synthesized Pd(II) complexes involved -NH group attached to C=S moiety. The 1H proton NMR taken in DMSO-d6 solvent consisted of a very broad peak at 4.8 ppm with an integration of 6. They are no functional groups in the structure of the complex causing a broad peak other than -NH. But the peak for -NH is found correctly as a sharp singlet at 8.5 ppm. The complexes are characterized by single crystal XRD and ESI-MS spectrum. So, what may be the reasons for such a broad peak in the spectrum and can we rely on such a spectrum? Is it due to the presence of D2O in DMSO-d6 interacting with the complex?
Could you show Picture of spectrum? Residual water in DMSO-d6 usually appears around 3.3
DMSO-d6 solvent residual should be a quintet at 2.5
i see a peak at 2.5 but it looks like a singlet so not sure if thats DMSO
its possible thats your water peak at 4.8 if its strongly binding to some groups on Pd complex but again, water is usually at 3.3 as broad peak but i dont see that
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