hi
I want to use UV-C lamps for deactivate corona virus (covid-19) in my air condition system .
With my researches , proper dose for deactivation of corona virus is about 47 j/m^2 (in average and without drop data).
Please help to chose proper UV-C lamp from its power and The right number for this important .
Refer to The Article: https://www.nature.com/articles/s41598-020-67211-2
Hope this gives the answer for the question
There is a lot of literature that can help. Here is a Google search:
https://www.google.com/search?q=uv+irradiation+of+covid19&rlz=1C1GCEU_en&oq=uv+irradiation+of+covid19&aqs=chrome..69i57j0l2.6568j0j7&sourceid=chrome&ie=UTF-8
I think the energy/area figure you show needs a time element. It should be in units of P/m^2. The longer you have to irradiate a volume the more effective the degradation will be. Further shouldn't it be volume (i.e. m^3).
There may also be a component of the UV producing ozone that can also kill viruses.
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