Pd- MWCNT is being used as a working electrode for glucose determination.
Sorry but the graph is recorded in the reduction part.... and starts at a potential were reduction occurs !!! so your electrode is probably not clean beginning the oxidative scan....
to measure an oxidation potential you must record the oxidation from a potential were no electrochemical reaction occurs and scan towards positive potential....
so forget this graph and redo your CV starting at a potential with nearly zero current and scan up to positive potential values, we will be able to compare the oxydation in presence or in absence of glucose
good luck !!
What is the electrochemical setup? Which electrodes did you use as your counter and reference? What was the electrolyte?
@ Hadar Ben- yoav sir thanx 4 ur reply. Hg/ HgO is used as a reference electrode and platinum as a counter electrode, Pd- MWCNT as a working electrode. Electrolyte used was 0.1 M NaOH.
It seems you have reactions from both solutions (with and without glucose). Can you subtract the curve without glucose from the one with glucose and see the difference?
@Hadar Ben- Yoak sir how can I substract the curve I have no idea.plz suggest me. However the difference in current in the presence of 2mM glucose is of about 200microampere .
You can take one data set (with the glucose) and subtract the other data set (without glucose) with any data analysis software (such as excel).
No one can estimate the redox potential from the given voltammogram. You can only determine "an appropriate potential for your operation". That's all.
Yusuke Okawa can you please let me know the appropriate potential for my operation.
For glucose detection by this electrode, the potential higher than ca 0.6 V vs. your reference electrode. You must choose an appropriate operation potential according to the background non-specific current and the required sensitivity. When you use the electrode for electrochemical detection for HPLC, you may choose 1.0 V (for example) for higher sensitivity. However, for batch experiments, the potential of 1.0 V may be too positive because of the non-specific oxidation of co-existing substances.
Advice: you should take axes in the voltammogram inverted. On the current electrochemistry convention, more positive (noble, oxidative) potentials are toward right. Anodic current is taken as positive. Your voltammogram obeys the "aincient" electrochemistry convention.
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