You will be familiar with spectroscopy in the visible and ultraviolet spectral range. In thisrange electronic transition are observed. The absorption of infrared radiation is the process that comes next at lower energies: theexcitation of vibrational and rotational transitions. The energy required for a transition is approximately a factor
of 10 smaller than for electronic transitions. The spectral region is adjacent to the visible spectral region and
extends from 0.7µm to 1000µm, which is the infrared spectral region. In most cases the region from 2.5 to
25µm is used.
Dear @DileepAhari,
Thank you for given your response..
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Regards
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Neeraj Meena
Thank you..
IR stands for Infrared. There are several types of infrared, high and low. It would be the ones used to detect heat from bodies.it is below the visible spectrum and below the red zone. The radio waves are the first ones
Dear all
Answer:-
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:-IR is a kind of radiant energy. Which can be seen from many distances with the human eye. But it is a shorter wavelength than radio waves. And its border becomes a little less visible by going near the red color. Because as it approaches the red colour, its wavelength gets spread. Which is approximately equal to 3×10^4m.
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Thank you ..
IR the portion of the electromagnetic spectrum that extends from the long wavelength, or red, end of the visible-light range to the microwave range. Invisible to the eye, it can be detected as a sensation of warmth on the skin. The infrared range is usually divided into three regions: near-infrared (nearest the visible spectrum), with wavelengths 0.78 to about 2.5 micrometers (a micrometer, or micron, is 10-6 meter); middle infrared, with wavelengths 2.5 to about 50 micrometers; and far infrared, with wavelengths 50 to 1,000 micrometers.
https://www.britannica.com/science/infrared-radiation
Dear all,
there are a lot of answers up to now, which in the meantime are sufficiently provided with recommendations;
but none of the answers is addressed to the primary question regarding 'energy' of IR.
For this, Neeraj Meena ,
please see for example:
https://en.wikipedia.org/wiki/Photon_energy
Here you will see the energy to wavelength relation:
E = h*c/lambda or E* lamdda=h*c; with 'E' being the photon energy, 'lambda' its wavelength, 'h' as the Planck constant and 'c' the speed of light.
According to the formula therein:
E (eV) = 1,2389/ lambda(µm)
you might calculate the energy by yourself.
By the way: sorry, but all this little stuff is part of undergraduate course of physics....
Respected sir,
First look carefully at the above question. There are some words whose depth you cannot understand. So understand it and then show your answer.
Thank you.
Sir Gerhard Martens,
I have mentioned earlier the answer by discussing with one of my friends. And in the question I discussed about Infrared radiation not to define an energy.
Dear Neeraj Meena ,
so why do you ask for 'energy' in the title line of your question when you do not want to know the 'energy'?
You should perhaps rephrase the title...
It is a type of radiant energy with longer wavelengths and this is what I can comment on your IR RADIATION question
Infrared radiation or thermal radiation is a type of electromagnetic radiation with a higher wavelength than visible light. Heating processes with infrared emitters stand out for their high profitability, because the heat energy is transmitted through electromagnetic emissions
Infrared radiation (IR), or infrared light, is a type of radiant energy that's invisible to human eyes but that we can feel as heat