Hello,
I have synthesized zif-8 using a three fold excess of 2-methylimidazole. I would like to purify the excess 2-methylimidazole from uncreated zinc nitrate (very little) and nitrate. What is the nitrate ion paired with after the reaction takes place. It is a weak conjugate base so very little will form nitric acid. Will it be paired with the reacted zinc in zif-8? Any clarification would be helpful.
Thank you,
Feras
It looks from the structure that the product is uncharged and could be partitioned from the aqueous phase into a suitable solvent.
Dear Feras Rabie, formally, zif-8 is the neutral zinc(II) salt of 2-methylimidazole. In the solvothermal method (see attachment) using excess 2-methylimidazole and DMF as solvent the zif-8 products precipitates from the reaction mixture and is purified by washing with DMF and methanol. As you used an excess of 2-methylimidazole (MeIM), the nitrate anion will end up as 2-methylimidazolium nitrate, [MeIMH]+[NO3]-, which is washed away with DMF and methanol. Thus it will not be paired with the Zn in the product.
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