Would the first step be dissociation of N2
N2 + 1n = 14N(7protons) + 14C(6 protons) + 1p(proton)
Will 14C remain as a particle or it is hot enough to react with O2 forming CO?
Can CO be further oxidized to CO2 if surrounding temperature is only 200 oC, would it provide enough activation energy?
What would happen to the remaining atomic nitrogen?
Dear Maria Ivanova,
Please find the links that could give you a lot of information regarding your question.
https://www.slideshare.net/FahidAsif/chemistry-9th-notes-punjab-text-book-board
Thanks!
This is just the basic chemistry slides. It has no information about what I am trying to figure out.
The capture cross-section for N14 is about a factor 100 smaller than the cross-section for elastic scattering. So most of the time the neutron does nothing. Even if it is captured, N15 is stable, so that you would only see gammas (the N15 can be in an excited state).
Dear Alexander,
Thank you very much.
I have seen in some nuclear plant reports (CANDU) that N14 becomes C14, which potentially can form CO or CO2. In those cases, it becomes a radiological hazard.
Have you happened to read anything about that?
If you look at https://www-nds.iaea.org/exfor/exfor.htm you can find, that there is a finite cross-section for the reaction 14-N(n,p)14-C (
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