Abhimanyu Singh, It is not possible to apply velocity and displacement to the same node in the same direction in FEA. This is because velocity and displacement are two different quantities. Velocity is the rate of change of displacement, so they cannot be the same. If you apply a velocity to a node, the node will start to move. If you then apply a displacement to the same node, the node will move in the direction of the displacement. However, the velocity of the node will not change.

The only way to apply velocity and displacement to the same node in the same direction is to apply the velocity first and then the displacement. The velocity will cause the node to move, and the displacement will add to the node's displacement. However, this is not a good idea, because it will create an inconsistency in the model. The velocity of the node will not be equal to the rate of change of the displacement. This can lead to inaccurate results.

So, if you are trying to apply 2 mm displacement along with 0.05 mm/s velocity in Abaqus, you will need to apply the displacement to one node and the velocity to another node in same step. You cannot apply them to the same node in same step. I hope it helps !

Abhimanyu Singh, Set step time 40s and 2mm displacement (Amplitude: Ramp, or ((0,0),(40,1))), the node (or nodeset) will move with velocity 0.05mm/s.

Do you mean applying displacement control load with a specified loading rate?

Ahmad Gamal Saad, yes, in the aforementioned scenario.

Abhimanyu Singh, To simulate a 2mm displacement at a loading rate of 0.05 mm/s, you can try either:

1- Get the strain rate corresponding to the experimental test loading with velocity (0.05 mm/s). Consider the effect of the strain rate on the used materials' stress-strain curves. Then, perform a general static displacement control with 2mm displacement.

2- Use the Abaqus Explicit solver with velocity loading. Set the velocity to 0.05 mm/s at the loading point and the time step to 40s.