THD = (sigma(V2^2+V3^2+V4^2+...Vn^2))0.5/V1 (1)
THD = (sigma(V2^2+V3^2+V4^2+...Vn^2))0.5/V1^2 (2)
Among these two equation which one is correct? Some journals mention (1), and others (2). For voltage profile management which equation is better?
Change your equation (1) : THD = (sigma(V2^2+V3^2+V4^2+...Vn^2))0.5/V1 To :
- THD = (sigma(V2^2+V3^2+V4^2+...Vn^2))^0.5/V1
then it will be OK. Please note the power symbol (^) before 0.5
BOTH EQUATIONS are correct, but you missed the subscript. The first one is THRR for "reference" and the second equation is THRF for (fundamental). In practice THRF is used.
See here for quick reference:
https://en.wikipedia.org/wiki/Total_harmonic_distortion
For technical paper, see here:
https://en.wikipedia.org/wiki/Total_harmonic_distortion
You have to compare like with like, as THD is a ratio of a measure of the ratio of all the harmonics compared to the funamental. The top equation is the correct one, but I am not familiar with the package you use to write these down. I believe the 0.5 I see should really be (^0.5), that is square root of... SQRT(Vx^2) has Volts as units, not volts squared, so the denominator should also be in Volts, i.e., V1, (or SQRT(V1^2)), or (V1^2)^0.5. Read a bit more, talk to your professors a bit more and you will be familiar with these concepts. Happy researching! Fernando
Change your equation (1) : THD = (sigma(V2^2+V3^2+V4^2+...Vn^2))0.5/V1 To :
- THD = (sigma(V2^2+V3^2+V4^2+...Vn^2))^0.5/V1
then it will be OK. Please note the power symbol (^) before 0.5
Of course Farhad Yadzi is right (I actually 'read' that, as it is obviously the square root of the sum of the squared values - a multidimensional pythagoras rule for the hypothenuse).
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