Can anyone simply clarify the specific volumes of oil and methanol used in the transesterification reaction considering any ratio 1:3, 1:8 etc...for Biodiesel production when using a heterogenous catalyst?
According to Sabah Mohamed Farouk, Aghareed M. Tayeb, Shereen M. S. Abdel-Hamid & Randa M. Osman, in the transesterification process for biodiesel production, the specific volumes of oil and methanol can vary depending on the type of oil used and the desired yield. However, a common ratio used in many biodiesel production processes is a methanol-to-oil volumetric ratio of approximately 6:1.
For example, if you use 1 liter of vegetable oil, you typically use about 6 liters of methanol. This ratio ensures enough methanol reacts with the oil's triglycerides to produce biodiesel and glycerol.
Additionally, the process often requires a catalyst, such as sodium hydroxide (NaOH) or potassium hydroxide (KOH), to facilitate the reaction. The amount of catalyst used can vary, but it is typically around 0.5% to 1% of the oil's weight.
Thank you very much for your reply sir. I wanted to mention that, based on my research, only volume ratios have proven effective for biodiesel production using a heterogeneous catalyst, rather than molar ratios.