Riku Imamura

You ask a specific question and the reference from Kaushick Parui, while a helpful text, does not answer your question. Couple of points:

• There are 2 parts to a refractive index (RI = n - i.k) the real and the imaginary (absorptive/light lost) part
• RI is wavelength dependent and you don't indicate what wavelength you're talking about - 1.55 microns?
• The level of erbium doping is relatively low and, as a first approximation the real part of the RI would be that of the material you're doping
• The imaginary component will depend on the level of doping as you say but it's not good (except for certain military applications) to have a high attenuation fiber so again the first approximation will be the attenuation coefficient of the bulk material and if you're modeling, I'd test this value along with others 1 and 2 magnitudes higher

Kaushick Parui needs to indicate where in the book (copyright issues?) your question is answered rather than providing a virtually meaningless url without context.

The attached paper may be of use if you haven't already seen it. Refer to Table 1 on 6/13.

Dear Alan F Rawle,

Thank you for the kind answer.

I should have asked a more detailed question about wavelengths.

I wanted to compare measured the RI of Er-doped silica, with the reference value, so the attached paper was very helpful.

Regards,

Riku Imamura