Here I mean to say that if I assume pulses of single photons, then because of Bandwidth theorem this can't be of single frequency. W. E. Lamb,Jr., “Anti-photon.” Applied Phys B 60, 77-84 (1995)
The 'photon energy' is hn, and the momentum is hk, where n is the frequency, and k is the wave vector. This is the standard association to plane electromagnetic waves. Since a definite frequency is a property of an infinite monochromatic wave, and the definite k-vector is the property of a wavefront of infinite transverse extent, this association defines an extremely nonlocal object. I am happy to see Lamb's paper quoted, where several misconceptions concerning the word 'photon' is discussed. To be very short, the basic point is that, to discreteness many physicist associate 'granularity' and sharp localization in space. (The temporal extent then is connected to the spatial one, by dividing the latter by c, the velocity of light.) A pulse of, say, finite duration is a many-mode and many-photon field, containing Fourier components, whose (disrete) excitation degrees are the photon population numbers. Lamb stresses to keep in mind that photons are not just localized packets, but in general they are excitation of the natural modes satisfying the proper boundary conditions, set by the experimenter (experimental apparatus). My answer is NO, to the question >> "pulses of single photons" is it a correct use of the word photon?
Thanks Mr. Sandor Varro for your nice comment. Surely I will go through the references suggested by you for more detailed understanding.
Please check (http://www.pivotalconceptsinscience.com)
for a proposed structure for the photon phenomenon.
You have to read about poissonian, sub-poissonian and super-poissonian distributions of photons to introduce your work conditions much more precisely. This is a matter of quantum optics and some detailed discussion before making such question would be of benefit
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