m encrypting an audio file in matlab successfully execute , but it is taking 16 values every time , as audio file has huge values when i divide audio file size with 16 it is giving me 689 .....means at every rotation it will return a cipher text n total cipher texts at the are 689 ...i m confused that how to embedd a bundle of cipher texts in any image...how much bits i need to embedd these cipher text .....or is there anyother way for encryption so that cipher text may decrease....??
my demo file
%AES_DEMO Demonstration of AES-components.
%
% AES_DEMO
% runs a demonstration of all components of
% the Advanced Encryption Standard (AES) toolbox.
%
% In the initialization step the S-boxes, the round constants,
% and the polynomial matrices are created and
% an example cipher key is expanded into
% the round key schedule.
% Step two and three finally convert
% an example plaintext to ciphertext and back to plaintext.
% Copyright 2001-2005, J. J. Buchholz, Hochschule Bremen, [email protected]
% Version 1.0 30.05.2001
% Initialization
[s_box, inv_s_box, w, poly_mat, inv_poly_mat] = aes_init;
% Define an arbitrary series of 16 plaintext bytes
% in hexadecimal (string) representation
% The following two specific plaintexts are used as examples
% in the AES-Specification (draft)
% plaintext_hex = {'00' '11' '22' '33' '44' '55' '66' '77' ...
% '88' '99' 'aa' 'bb' 'cc' 'dd' 'ee' 'ff'};
%plaintext_hex = {'32' '43' 'f6' 'a8' '88' '5a' '30' '8d' ...
% '31' '31' '98' 'a2' 'e0' '37' '07' '34'};
% % x = fopen('D:\MATLAB\AES\Aa.txt', 'r');
%
%
% %
% a = a(1:16);
% size(a);
[plaintext1,fs]= wavread('A1.wav','native');
plaintext1=plaintext1(1:16);
plaintext_hex=dec2hex(plaintext1);
plaintext = hex2dec (plaintext_hex);
plain =[];
for i = 1:11025
plain[i]=plaintext1(1:16);
end
size= length(plain);
% Convert plaintext from hexadecimal (string) to decimal representation
% This is the real McCoy.
% Convert the plaintext to ciphertext,
% using the expanded key, the S-box, and the polynomial transformation matrix
for i = 1:size
ciphertext = cipher (plain(i), w, s_box, poly_mat, 1);
end
Hi, Amina Dilawar Good Afternoon
An important characteristic underlying the design of image processing systems is the significant level of testing and experimentation that normally is required before arriving at an acceptable solution. This characteristic implies that the ability to formulate approaches and quickly prototype candidate solutions generally plays a major role in reducing the cost and time required to arrive at a viable system implementation. As development tool, we used MATLAB 7.0.1 along with its signal processing and image processing toolbox.
This powerful tool is a high performance computing language for technical computing, which integrates computation, visualization, and programming in an easy-to-use environment where problems and solutions are expressed in familiar mathematical notation. MATLAB is an interactive system whose basic data element is a matrix. This allows formulating solutions to many technical computing problems, especially those involving matrix representations, in a fraction of the time it would take to write a program in a scalar non-interactive language such as C. You can apply the use of MATLAB in every step of the project, from reading the picture to the reading of the audio file with a frequency spectrum from a spectrogram code.
Kindly refer the following two journal papers:
1. Y. K. Lee and L. H. Chen. (2000) “High Capacity Image Steganographic Model.Vision, Image and Signal Processing, IEEE Proceedings, pp.288-294.
2. K. David. (1996) “The History of Steganography,” Information Hiding: First International Workshop . Lecture Notes in Computer Science, pp. 1-5.
All the best. Thanks.
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