M=m0/square-root(1-v²/c²) were false?

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Sreenatha N R

This equation applied for the particle moving with relativistic speed.

Paul Pistea

no, the equation applies for all moving particles with mass; at very high speeds SR(1-v²/c²) has a greater value.

again: while virtual particles (higgs-boson) has no mass (that is "maybe" equal zero) and turned into a particle with mass (not zero!), M=M0/SQT(1-v²/c²) is NOT valid. so the process is NOT RT conform.

this is NOT a question! it is an ascertainment!!

Ramzi Suleiman

I agree with Paul. In fact, Special Relativity theory is not even wrong!

See my paper: On the Naturalness and Generality of the Relativity Principle.

Ramzi