Implicators and t-norms are fuzzy operator. I try to find a couple of t-norm and Implicator with respect to always t-norm values be upper than Implicators.
Antoon Bronselaer
If you mean that you are looking for a t-norm T and an implicator I such that T(a,b) >= I(a,b) for all a and b, then I don't think this is possible.
Consider a=0, then you know that I(a,b)=1 and T(a,b) =0, regardless of T, I and the value of b.
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Antoon
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