I am just wondering if any one here knows the relationship of impedance, inductance, capacitance, and frequency. I have seen equation, but it is only involves the relationship of frequency, inductance and capacitance.
Dear Macana,
When Ohms Law is described in two current impositions, in addition to the ordinary Ohms law E=IR, for DC
It is E= Current* IZ(w)I, for AC
Here the IZ(w)I involves the magnitude of impedane containing the elements of an equivalent circuit such as capacitance and inductance. As you may know that w (omega) is the the angular frequency.
The concept has been well described in " Electrochemistry and Corrosion Science" by Nester Perez, Chapter 3.
It may help to reach the answer. Wish You all success.
In a passive, linear time invariant circuit and without transformers and internal sources, if you have lumped components, only three independent parameter types: L, C, R define the circuit. Frequency is given by the applied excitation to the circuit. The impedance seen at any port of the circuit resumes the behavior of the circuit in response to the excitation: If the excitation is a voltage, current through the circuit port depends on the impedance seen at the port. Thus, impedance at the port depends on the internal component values and the applied frequency. [Of course, applying Thevenin theorem to some circuit part, you can replace that part by an equivalent impedance].
Hello Roland,
I think the relation between the passive components (R, L, and C ) and frequency, it depends on the connectivity among them. In other words, it depends on your network (Parallel, Series).
Regards.
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