BIOWASTE : 23750 TONS/ANNUM
DRY MATTER : 30 PERCENT i.e 7125 T/A
ORGANIC DRY MATTER(VOLATILE) : 70 PERCENT i.e 4987.5 T/A
Digestate(40% DM)
ODM/DAY = 4987.5/365 = 13.66 T/A
Is this the feedstock for my process ? In dranco feed is added in the ratio 1 part fresh feedstock : 6 parts of digestate. Then, What will be total feedstock for my system ? Also, Considering HRT =20 days then what will be the volume of my digester/reactor and Organic Loading rate ? PLEASE CLEAR THIS DOUBT
Hello Pratim,
Organic loading rate is the amount of organic material (for instance kg CODt/ l water) feeding into the unit volume of digester say in a day...means kg CODt/m3.d. This means if you have shorter HRT, you may have high OLR feeding or for longer HRT less OLR feeding.
Sunil
just follow the textbooks, Pratim
as stated by Sunil, OLR descripts the amount or organics (as COD or, in your case as VS, [T] or [KG]) loaded to a system volume [m3] per time ([A] or [D]). In a AD system with recycling, the recicling should be included into the system boundaries. So your OLR only depends on the raw input material and the volume of your digester.
With a raw flow of 23750 T/A = 65 T/D and a HRT of 20 D you'll end up with a volume of 1301 M3. The resulting OLR will be 13.66 T VS / 1301 M3*D = 0.0105 T*M*/d = 10.5 KG/M3*D, which is in the usual range for high solids digesrets as Dranco.
Urs
Assuming waste density of 1 ton/m3. 65 T/D~65 m3/D for the estimation of the reactor volume.
Yann
the most important assumption in comparing OLR with digester volume is IL = 1 Kg of feedstock.
the first step is to find the required (available) feedstock that will be added to the digester on daily basis. if you have 2000 Kg of feedstock on daily basis and mixing ratio of say 3:1 then you require 8000 L digester active volume, this volume it requires about 3000 L of biogas holder (storage) immediately after the active volume. the total digester volume will be 11,000 L
If your design is based on TS or VS, you have to characterize your feedstock first and know the mentioned characteristics. normally 1 Kg of dung contains about 40 to 20 % TS . so 40 % of 8000 is 3200 L
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