Sameh Boukerche
0.5gm = 0.5×106 µg
Dissolved in 1 ml
The solution concentration = 5×105 ppm (0.5×106
But the active ingredient is 0,14 %
The solution concentration = 5×105 ×0.14 = 70000 ppm
Sorry Sameh Boukerche
I had a mistake
Samaneh Mahmoudvand
In a simple way:
0.5 gm = 0.5 ×106 µg
every 100 gm of the product had 0.14 gm active ingredient
So, 0.5 ×106 Had how much ……………………...? active ingredient
Amount of Active ingredient in the product = 0.5 ×106×0.14/100= 700 µg
Concentration (W/V) = Weight of dissolved(g)/Volume of Solvent(L)
Ppm = 1 gm/ton = 1 mg/L = 1 µg/ml
For the sample 0.5 gm dissolved in 1 ml
The true concentration (active ingredient) = 700 µg
1 µg/ml =1 Ppm
700 µg/ml=?
Conc. ppm = 700 ×1/1 = 700 ppm
With my best wishes
Sabry Abdallah Thank you for your answer, but 1 ppm is it not equal to 1 ul/L ?
Dear Sameh, there are two ways to express parts per million (ppm): in milligrams of solute per kilogram of solution (mg/kg) or per liter of solution (mg/L). The last one is the most used, and as Sabry Abdallah pointed out, it can also be expressed as ug/mL. But I am afraid that with the data you have given us it is not possible to calculate this concentration exactly without the final volume of solution. Let me explain: when dissolving 0, 5 g of the powder in 1 mL of water, the final volume of solution will be greater than 1 mL. Can you measure that volume in any way?
In any case, the calculation is as follows:
ppm = 0.5 g x (0.14 g / 100 g) x (1000 mg / 1 g) / V
Where:
- 0.5 g x (0.14 g / 100 g): grams of the active ingredient.
- (1000 mg / 1 g): factor to convert grams to milligrams.
- V: final volume of solution in liters.
Postscript: without V an exact calculation can be made but in mg/kg.
By the way Sameh Boukerche, you mention that the powder is volatile, what do you mean exactly? What sublimates or what is very light?
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