Dear Orhan,

in weight percentages:

• [Fe2O3(t)=FeO(t)*1.11134];
• [FeO(t)=Fe2O3(t)/1.11134]; or [FeO(t)=Fe2O3(t)*0.8998]
• [Fe2O3(t)/FeO(t)=1.11134] is the weight ratio of iron.

Your formula look fine to me. I just rewrote them because the way RG formats formula is very confusing.

Kind regards,

Samuele

Dear Samuele,

Thank you very much for your valuable comment.