I need these conversions for sedimentary rocks // FeO= Fe2O3*0.8998 // FeO (t)= Fe2O3/1.11134 + FeO // Fe2O3 (t)= FeO (t)*1.11134 // Are these cor.?

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Samuele Papeschi

Dear Orhan,

in weight percentages:

[Fe2O3(t)=FeO(t)*1.11134];
[FeO(t)=Fe2O3(t)/1.11134]; or [FeO(t)=Fe2O3(t)*0.8998]
[Fe2O3(t)/FeO(t)=1.11134] is the weight ratio of iron.

Your formula look fine to me. I just rewrote them because the way RG formats formula is very confusing.

Kind regards,

Samuele

Orhan R. Abbasov

Dear Samuele,

Thank you very much for your valuable comment.