Hi all

I am trying to fit a prediction equation for spirmoeric parameter (fev1/fvc%) the maximum possible number for fev1/fvc is 100

I tried the following :

> gen.trun(par=c(100),family="BCCG", name="to100", type="right")

A truncated family of distributions from BCCG has been generated

and saved under the names:

dBCCGto100 pBCCGto100 qBCCGto100 rBCCGto100 BCCGto100

The type of truncation is right

and the truncation parameter is 100

> mm.fevfvc gen.trun(par=c(log(100)),family="BCCG", name="rlog", type="right")

A truncated family of distributions from BCCG has been generated

and saved under the names:

dBCCGrlog pBCCGrlog qBCCGrlog rBCCGrlog BCCGrlog

The type of truncation is right

and the truncation parameter is 4.60517

> mm.fevfvc