Square planar Pt(NH3)2(NO3)2 exists both in the Cis and Trans forms. Will the two isomers give same or different products with oxalic acid ? Please write equation/s in your answers.
Thank you.
Hello Monohar
I tried to find if NO3- has any trans effect/influence but I could not find it,
The NH3 is weak trans-director
The other questions are: the oxalate will displace NH3 or NO3-? and is oxalate going to be a bi-dentate or a mono-dentate ligand?
We need your help before giving final answers
When cis or trans-[Pt(NH3)2(NO3)2] isomer is reacting with another ligand, the leaving group is not going to be NH3 because the Pt-NH3 bond is too strong and the trans effect of NO3- is not high enough to split this bond. In both cis and tran forms the NO3- ligand which is a weak base is likely to dissociate. Therefore, reacting of cis form with oxalic acid should give [Pt(NH3)2(C2O4)] in which oxalate is acting as bidentate ligand through oxygen atoms of both carboxylic groups of oxalate. For the trans form, however, it not possible for the oxalate ion to be a bidentate ligand and reacting of the trans form with oxalic acid is expected to produce trans-[Pt(NH3)2(HC2O4)2] in which the oxalate ion is monodentate ligand. The reasons for the fact that NO3- is not a high trans director ligand are (i) it is not a very strong base like H- and (ii) it is not a pi accepting ligand such as CO.
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