I have a text file which shows the daily temperature of a specific location in 20 years. Therefore, there are total 365x20=7300 data. What should I do in python if I want to print only the largest 18 value per each 365 data? Therefore, the output file should have 18x20= 360 data. As I am new to python, I appreciate it if a suggestion of a possible code including how to import and output the file could be provided.
Thank you very much and the text file is attached below.
Hi,
Please note that your file contains 22500 temperature values. So, I have written code to take the first 7300 values. Find the attached python code, comments explain the use of each line.
For fast and best answers, I suggest you use stackoverflow to ask python questions.
Hello Li Andy,
I'm starting to learn Python too, so mind my code if it's a bit rudimentary. But it does the job! For the file you provided (test7.txt), there are 22500 temperatures/days, so that's 61 years and 235 days.
I've attached the code and the output. You could use it for other .txt files that follows the same temperature format. If you don't understand some line of code, please, let me know and I'll provide explanations!
Have a nice day.
Hello Li Andy,
if there is no additional hidden complexity in your problem specification, then this can easily be done using list comprehensions which is also more pythonic than nested for-loops.
@Pablo González Navarro
You might want to consider list comprehensions for your code as well (see https://docs.python.org/3/tutorial/datastructures.html#list-comprehensions).
Best, David
I prepared a simple script for your aim; you can import it in a simple loop for all.
file1=open("test7.txt", "r")
list1=[]
Max=[]
for i, L in enumerate(file1):
list1.append(float(L))
for i , Lm in enumerate(list1):
if i < 365:
Max.append(Lm)
print sorted(set(Max), reverse=True)[0:18]
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