Amps and Volts of the power supply.

Dear Sir Jerry Decker

I sincerely thank the professor for taking care of my question, but to be better than Sir please give me more details. I hope Sir always healthy.

Take advantage of the wavelength of voltage applied to the reactor and the associated discharge current. Follow the current voltage variant applied to the Dielectric Barrier Discharge Reactor, where it reaches the value of the starting point, and keep the reactor discharge current. Random distribution of threads on the surface of the entire electrode. Signs are placed on the surface of the insulating medium, and the charges are built in then the neighborhood. This starts with an electric field that conflicts with the applied field. After a very short period, the activity of thecharge disappears in that spot, followed by a start at another location. At the peak of the applied , the displacement current across the dielectric is zero and the streamer activity stops.

Dear Sir Jamal Amous

Thank Sir for your reply. I feel very happy because Sir spent time response to my problem. But I still really not clearly the method calculate Discharge power of DBD reaction using V-Q Lissajous method. Please help me detail a little. Thanks, Sir, so much!

My son;

Assalamo alaikom (hello)

Hope that you are well.

The DBD discharge you generated in your reactor {with its own geometry (my be cylindrical or planner)} By powering it via a voltage obtained from a transformer. You have your own isolated electrodes with glassy slides .These electrodes are separated apart with a distance of approximately few mm . When the applied Ac voltage reaches zero(onset) ,then the discharge starts in the space between the isolated electrodes inside the reactor, with a random distribution on the surface area of the isolated electrodes ,thus building a charge on the isolating space gap. By doing this an opposite field against the applied AC is formed . By time this field extinguishes simultaneously with the initiation of streamers activity in another location . For dV/dt=0 ,no currents cross the gap between the electrodes and no streamer activity is observed then! The power consumption is to be deduced applying the Lissajous figures method.

If you can use this method then you can find your answer.

I do recommend you to investigate the following articles:

1-M. Abdel-Salam, A. Hashem, A. Yehia, A. Mizuni, A. Turky and A. Gabr, J. Phys. D: Appl. Phys.,36(2003) 252.

[2] A. Yehia and A. Mizuno, J. Appl. Phys.,98(2005) 3051 .

[3] K.Takaki,Y.Hatanaka,K.Arima,S.Mikaigawa,andT.Fugi wara, Vacuum,83(2009), 128 .

[4] R.V.Barrientos, J.P. Sotelo, M.P.Pacheco, J.S.B.Read and R. L. Callejas, Plasma Sources Sci. Technol.15(2006) 237. [5] Z. Falkenstein and J. J. Coogan, J. Phys. D,30(1997) 817.

Good luck with success.

Professor Jamal Amous

Dear Professor Jamal Amous

I sincerely thank the profound help from the professor. The articles the professor gave me, I found it really useful for me at this time. I will follow the studies the professor gave me carefully and meticulously. If possible, I would love to know the professor's email address so that I can exchange and learn from the professor more and more frequently.

Once again, I would like to thank the professors for your valuable hel !

Maybe fast trace oscilloscope.

Ha Khanh Hop ,

You can also take a look at:

Article Progress Toward Accurate Measurement of Dielectric Barrier D...

The paper describes very well the techniques for power measurements in DBD plasma actuators, and can be extended to almost all kinds of APPJ.

Dear Professor Fellype Do Nascimento !

I sincerely thank Professor for taking care of my questions. Professor's article sent for me a precious reference for me at this moment. I will definitely take the time to consult this valuable document carefully.

I hope Professor can send Professor's email address so I can exchange directly to Professor in the future in the field of studying this plasma.

Once again, I would like to thank the professors for your valuable help!

I would recommend my work about this topic

Article The Equivalent Circuit Approach for the Electrical Diagnosti...

Discharge power will measure by the integration of instantaneous voltage and current as shown below:

integration of instantaneous voltage and current

Discharge Power,P(W)=f× int(0 to T) (V(t)I(t) dt)

Where: f stands for frequency

T is period of the cycle

We used the trapezoidal rule for the calculation with V(t) and I(t) are the data recorded through oscilloscope.

What need to do:

1. Number of points (row in the excel file) for one cycle

2. Interval sample during recording data, it stands for dt

3. A(t) =V(t) x I(t) x dt

4. Sum of A(t) for one cycle, and multiply with the frequency we can get the discharge power

Note that if you measured the voltage drop through the resistor, so you get the current by dividing the recorded voltage by the resistor that was used as a current probe.

Dear Hop

You can easily calculate the discharge power and energy of your discharge using QV plot.

What you need to is:

1: Calculate the total capacitance, capacitance of the dielectric and capacitance of the air space.

2: Total capacitance (CT) and the capacitance of the dielectric (Cd) can be obtained from the slope of your Lissajous figure.

3: From the measured value of these capacitance, you can get the value of the capacitance of air space (Ca) using the formula

1/CT = 1/Ca + 1/Cd

4: Now you can simply plug in the equations to get the discharge power and energy dissipated per cycle.

5: Energy E = 4 *V(min)*[V(max) - V(min)]*Cd*{Cd/(Ca +Cd)}

6: Power P = 4 *V(min)*[V(max) - V(min)]*Cd*{Cd/(Ca +Cd)}*f

Here; V(min) is the minimum voltage necessary to ignite the discharge and V(max) is the maximum applied voltage. You can get these two values from the QV plot.

Similarly, f is the frequency of the input source.

Hey Mr Rajesh,

Could you please tell me from where the 4 comes in the formula?