Thank you James Demers sir for your suggestion. Can you brief us about the volume of each sample to be prepared according to concentration (i.e.- 1.93 mM Metol, 68.6 lM copper and 1 mM acetic acid/sodium acetate buffer of pH 5.4).
You have 2 options: either you can prepare 100 mL of solution with the same concentrations and use only 3 mL or you can prepare 100 mL solution with 5 times concentrations and then dilute it 5 times until you get 20 mL of desired concentrations. Hope this helps
There is no reason about it sir James Demers . your are saying like I should weigh metol (1.93) and copper salt (68.6) and to add in appropriate volume of buffer. Am I correct sir or any changes.
Thank you for suggestion Timur Ashirov sir. But we are having 3 reagents sir with that we have to makeup it to 3 ml solution. Is it possible with your suggestion method sir ?
i) While considering an acetic acid / sodium acetate buffer solution:
The pKa of acetic acid is 4.75, from what we can only expect fair pH buffering effect between approx. 3.75 to 5.75. The pH of acetic acid / sodium acetate buffer solutions can be simply calculated based on the Henderson-Hasselbalch equation, after the molar concentrations of acetic acid (Ca) and sodium acetate salt (Cs) at the buffer solution: pH = pKa + log10(Cs/Ca); what can be generally expected to hold for Ca > 100Ka. A possible derivation for this equation, along with a justification for the stated minimum concentration limit for its validity, can be found elsewhere at this forum: https://www.researchgate.net/post/pH_calculation_of_a_mixture_of_formic_acid_NaOH_and_water
ii) Simply dissolve metol and the copper salt in above sol. according to the intended M conc. (i.e. mol solute / dm3 of the final solution containing both solutes, metol and the copper salt).