I used 3 electrode potential state to scan the CV for electrochromic properties of tungsten oxide (WO3). The potential start at -1.5 V scan range from -1.5 to 1.5 V using Ag/AgCl as a reference electrode and Pt as counter electrode. 0.5 M LiClO4 is used as electrolyte. I have a few questions:
1. Which peak belong to oxidation and reduction reaction in the system?
2. why 2 peaks in negative current (at low scan rate) combined together at the higher scan rate?
3. If i have to calculate the diffusion coefficient D(Li+) , which scan rate i should use for the calculation (low or high)? if in the negative current, they have 2 peaks which peak i should use for the calculation ? Do i need to combine the D value from 2 peaks , if i want to compare with the peak in positive current area (which only peak appear)?
Thank you,
Ploy
For proper understanding, please read the following books.
Guide to Experiments and Applications
By: F. Scholz
Fundamentals and Applications, By Allen J. Bard and Larry R. Faulkner
Your voltammogram is not very complex. All the features are explainable for your system. Please, go through the books for a better understanding of an electrochemical system.
Best,
Chandan
Dear Kunyapat Thummavichai,
Do you use PC or DMSO as a solvent?
1. An oxidation process going on at positive current always and reduction process always with negative current.
2. It can be happened when the increasing of overpotential vs speed rate not equal for two peaks
3. Also, left one could be not a peak for WO3 but peak of solvent decomposition, if so, you should use the right one, I think so.
Hope that you will be sitisfied by my answer.
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