I imagine a lot of detail will be lost during the asking of this question, but I will try my best.

I am using Gaussian to work through a reaction mechanism, roughly 15 steps. We believe the 10th transition state sits somewhere between a protonated C-N+(H)= imidazole ring and then the deprotonated state C-N=   Once the proton comes off, the 11th transition state is the removal of an OH group and the rearrangement of the double bond in the imidazole group. 

I have two questions. 

1) Does the -N+(H)= -N(H)=  involve a transition state?

2) I can always optimise -N+(H)= but I have never been able to optimise the protuct, -N(H)= and hold the + charge proton to the explicit water environment (I have tried up to 8 water molecules with PCM). The charge eventually moves out of the water back onto the nitrogen. Any idea how to keep the + charge in the water.

I have tried removing the -OH group as part of the removal of the proton from -N+(H)= but because the system has a +`charge, I end up with a protonated hydroxyl group and a long but still covalently bound (H2)O+-C bond.

More Anthony Nash's questions See All
Similar questions and discussions