Numerous journals reported the preparation of metal complex into a concentration of 1.0×10-3 mol/cm3 in dimethylsulfoxide (DMSO) solutions or 10-3 M. From my understanding (let say my complex MW is 500) 5 g of my complex is needed in 10 ml of DMSO. I`m not sure either this is the right calculation. How much actually in gram (let say my complex MW is 500) of my metal complex needed if I want to dissolve into that particular concentration.
Before you do anything, is your concentration 10-3 mol/cm3 or is it 10-3 M (mol/L)? These are different by a factor of 1000
First, your solvent does not have to be DMSO, you can use a solvent that dissolves your complex without causing any changes to it. You can use water, ethanol, or acetonitrile depending on your complex.
Second, 0.001 M means that if you use 10 mL to dissolve a 500 g/ mol molecule, the mass you need would be 0.005 g not 5 g.
Before you do anything, is your concentration 10-3 mol/cm3 or is it 10-3 M (mol/L)? These are different by a factor of 1000
Thank you for the answer Mr Khaleel. The concentration needed is 10-3 M dear Ms Mccormick.
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