Dear Bommineedi Lakshmana Kumar

1- Balance the charges stored on two electrodes (Q+ = Q-), and the mass loading ratio of electroactive materials on two electrodes is obtained using the following equation:

𝑚+/𝑚− = (𝐶−×Δ𝐸−)/(𝐶+×Δ𝐸+)

where 𝑚, 𝐶 and Δ𝐸 are the mass of active material, capacitance and potential window of the electrode, respectively; “+” and “-” represent positive and negative electrodes, respectively.

2- The capacitance of the assembled asymmetric supercapacitor device is calculated as follows:

𝐶𝑠 cell = 4x(𝐼 ∗ Δ𝑡)/(Δ𝑉 ∗ 𝑚), where m is the total mass of active materials on both two electrodes.

You may take a look at the following references:

Article W18O49 nanowires-graphene nanocomposite for asymmetric super...

https://doi.org/10.1021/acsami.8b14138

I hope this helps,

Best regards,

Thank you Mohammad R. Thalji .Thank you for your reply and important references too.

In the above formula, you have given capacitance C+/-, here capacitance means electrode capacitance (3 electrode system) and also specifically in the same electrolyte. If both electrodes show good electrochemical output but in different electrolytes then in that case.

Dear Bommineedi Lakshmana Kumar ,

After mass balance and ASC (asymmetric supercapacitor) fabrication.

The specific capacitance (Cs, F g-1) can be calculated using this formula from GCD data.

Specific Capacitance (Cs)= (2I ×∫V dt)/(m×(∆V)^2 )

where I is the current (A), ∫V dt is the integrated area under the discharge curve, M is the total mass of the active electrode materials (anode+ cathode) (g), and ∆V is the working potential window (V). This formula is more reliable than

𝐶𝑠 = 𝐼 ∗ Δ𝑡/(Δ𝑉 ∗ 𝑚).

As you said "both electrodes show good electrochemical output but in different electrolytes". In that case, not possible to use both electrolytes for device testing. Hence, for the ASC performances testing we need specific capacitance value of anode and cathode materials in common electrolyte.