To synthesis poly(Styrene methylmethacrylte) I took 14.065g  (135mmole) of styrene and 4.515g (45mmole) of methylmethacrylate in 70ml of methanol and 0.303g of AIBN initiator to do solution polymerization.  From the proton NMR of Poly(S-MMA) i found ration of Styrene and MMA part is 1:1.18  total product amount is 9.4896g. How can I calculate percentage of yield?  and what type of copolymer ( alternatating, random, bolock) form and how to calculate reactivity ratio ?

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