Hello Manav

Knowing flat-band potential value (for film electrodes composed of nano-particles) using Mott-Schottky plots (1/C2) vs. (Applied potential) gives a clue. Then you need value of band gap . Together they give positions of bot VB and CB edge positions.

Good luck

Hello Manav

Knowing flat-band potential value (for film electrodes composed of nano-particles) using Mott-Schottky plots (1/C2) vs. (Applied potential) gives a clue. Then you need value of band gap . Together they give positions of bot VB and CB edge positions.

Good luck

It can easily be done via XPS. From here, you can calculate the valance band edge and then by knowing its band gap from Tauc plot, we can calculate the position of conduction band as well.

Hello Hikmat Hilal,

How to find out flat - band potential from Mott-Schottky plot? Is it by taking the x-intercept of M-S plot ? I have put this question some time back in research gate; but couldn't get a satisfactory answer. From my experience with MOS structure I have found that the x-intercept gives the flat band voltage only when there are no oxide charges,mobile charges or interface charges which practically is not the situation. If the band bending is due only to metal - semiconductor work function difference this technique works. I will be highly obliged if you can shed some light in to this aspect.

Second point is concerning Manav's question about nanoparticles. Here my doubt is if nano particles form the electrodes then which material will form the film?

Another requestis to Muhammad Ehsan. Could you please elaborate on the technique to find the valance band edge from XPS data?

With thanks and regards

Rajeev.

Hello Rajeev Kumar,

I am not talking about electrodes. My question is simple:

I have nano composite materials synthesized by mixing nanomaterials-1 and nanomaterials-2. Now I am checking its photo-catalytic activity. So for electron transfer reaction during photo-catalytic activity of nano composite; one nanomaterial will transfer electron to other.

For this, I want to calculate value of VB & CB so that one can identify electron donor and acceptor.

Thanks & regards,

Manav

Thank you Manav. But my question was to Hikmat Hilal concerning his answer to your question. His answer contained a line like this "Knowing flat-band potential value (for film electrodes composed of nano-particles) using Mott-Schottky plots (1/C2) vs. (Applied potential) gives a clue". Because to get a capacitance value you require two electrodes and a dielectric film. It was not clear to me from his answer what he intended.

Regards.

I agree with Prof Hikmat Hilal

The optical band gap can easily be calculated from diffuse reflectance spectra. Once u have that then you can use the following equation. 

Vb=X-e+0.5eg under correction. X is the electronegativity, e is 4.5 eV. Once u have this u can just subtract tjis value from ur

Hallo, 

Can someone tells in more detail about finding VB and CB energy from Mott Schottky plot? I have Flat bend potential values.

Thanks