I know the simple formula that is used to determine the nuclear spin multiplicity of a molecular species. However, I would like to know how this quantity is measured for a linear radical N2H+ and how this differs from the calculation for the species HCN? Are these values tabulated for the different molecules?
Update: Could someone verify whether this is correct or not?
The nuclear spin multiplicity of N2H+ is 2 since the overall spin of the molecule on account of the unpaired electron is 1/2. For HCN, the nuclear spin multiplicity is 1.
Courtesy of Carlo di Lauro:
The nuclear spin multiplicity w is equal to the total number of nuclear spin functions.
The multiplicity is formed by the independent combinations of products of the spin functions of the separate nuclei, w is the number of such products, which is equal to the product of the spin multiplicities of all nuclei.
Thus for HCN we have: w=2x1x3=6
For N2H+, we have: w=3x3x2=18
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