I try to calculate by using the FeO= Fe2O3T*0.8990…whether this correct????
If this correct, why the calculated values are less in comparison to other’s data???
I want to convert FeO for calculating Mg# of peritotites….
A factor is the sum of the atomic weights of the elements in the required formula divided by the sum of the atomic weights in the original formula.
The factor to convert Fe2O3 to 2FeO is 2 x (55.85 + 16)/(55.85 x 2 + 16 x 3) = 0.8998 while the factor to convert 2FeO to Fe2O3 is 1/0.8998 = 1.1113.
Dear Madam
I could not understand the Equation you have written on the first line...
FeO=FeO 0.8991*Fe2O3
I believe its should be FeO=Fe2O3T*0.8991.....
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