i will do synthesis of coumarin using 10 mmol of salicylaldehyde and 10 mmol diethyl malonate using 10 mol% of catalyst L-proline. could anyone help me to count how much catalyst (in mg) should i use?
Swapnamoy Ganguly
If you use 10 mol% of L-proline catalyst, it's 0.1 equivalent to the salicylaldehyde (assuming it to be the limiting compound 1 eq.). So, the mmol of the catalyst will be (10X0.1=1 mmol) and hence the amount will be (1X115.13 = 115.13 mg) (MW of L-Proline = 115.13 g/mol).
Hope this answers your question Rafina Naqiyya Qatrunnada
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